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Memory Units Quiz 19 (10 MCQs)

This set of multiple-choice questions evaluates understanding of ALU components, register functions, and various memory units including cache, non-volatile memory, and data storage hierarchy. It tests knowledge of data buffering, temporary storage, and memory types such as static and dynamic memory. Concepts like CPU addressability, EMS software, and virtual memory management are also covered.

Quiz Instructions

Select an option to see the correct answer instantly.

1. Which of the following circuit is used as a 'Memory device' in computers?

Correct Answer: Correct answer is: (B) Flip Flop.

Exam Relevance: GATE, GRE, ECE exams, Computer Science exams

Difficulty: Moderate

Concept notes: A flip-flop is a fundamental building block in digital electronics used to store binary information. It acts as a memory device by holding a single bit of data.

Common Mistakes: A common mistake is confusing a flip-flop with other digital circuits like rectifiers, comparators, or attenuators, which do not function as memory devices.

Explanations: A flip-flop is a bistable multivibrator that can store one bit of data. It has two stable states and can be switched between these states by input signals. This ability to hold a state makes it a memory device, which is essential for storing data in computers.

Option Analysis:

Option A: A rectifier is used to convert AC to DC and does not function as a memory device.
Option B: A flip-flop is a memory device used to store binary information.
Option C: A comparator compares two input voltages and does not store data.
Option D: An attenuator reduces the amplitude of a signal and does not function as a memory device.

2. What type of memory is not directly addressable by the CPU and requires special softw3are called EMS (expanded memory specification)?

Correct Answer: Correct answer is: (B) Expanded.

Exam Relevance: CompTIA A+, Microsoft Certified: Windows Operating System Fundamentals

Difficulty: Moderate

Concept notes: Expanded memory is a type of memory that is not directly addressable by the CPU and requires special software called EMS (Expanded Memory Specification) to access.

Common Mistakes: A common misunderstanding is that extended memory is not directly addressable by the CPU, but it is actually the expanded memory that requires special software.

Explanations: Expanded memory is a type of memory that is not directly accessible by the CPU. It requires special software called EMS (Expanded Memory Specification) to manage and access this memory. This is different from extended memory, which is directly addressable by the CPU in protected mode. Base and conventional memory are directly accessible by the CPU without the need for additional software.

Option Analysis:

Option A: Extended memory is directly addressable by the CPU in protected mode and does not require special software.
Option B: Expanded memory is not directly addressable by the CPU and requires EMS (Expanded Memory Specification) software to access.
Option C: Base memory is directly accessible by the CPU and does not require special software.
Option D: Conventional memory is directly accessible by the CPU and does not require special software.

Mnemonic: EMS for Expanded Memory

3. In virtual storage, program segments stored on disk during processing are called:

Correct Answer: Correct answer is: (C) Pages.

Exam Relevance: Operating Systems, Computer Architecture, Advanced Placement Computer Science

Difficulty: Moderate

Concept notes: In virtual storage, program segments stored on disk during processing are called pages.

Common Mistakes: A common misunderstanding is confusing pages with other storage units like blocks or sectors, which are used in different contexts.

Explanations: In virtual memory systems, the operating system divides the program into smaller units called pages. These pages are stored on disk and brought into main memory as needed. This allows the system to manage memory more efficiently by swapping pages between disk and main memory.

Option Analysis:

Option A: Tracks are concentric circles on a disk where data is stored, not program segments.
Option B: Blocks are fixed-size units of data used in file systems, not specifically for program segments in virtual memory.
Option C: Pages are the correct term for program segments stored on disk in virtual memory systems.
Option D: Sectors are the smallest addressable unit on a disk, not program segments.

Mnemonic: Paging Pages, Not Blocks or Sectors

4. A memory that does not change its contents without external causes is known as

Correct Answer: Correct answer is: (B) Static memory.

Exam Relevance: Computer Science Exams, Electrical Engineering Exams, IT Certification Exams

Difficulty: Easy

Concept notes: Static memory refers to a type of memory that retains its contents without the need for periodic refreshing or external causes.

Common Mistakes: A common misunderstanding is that dynamic memory also retains its contents without external causes, but it actually requires periodic refreshing to maintain its data.

Explanations: Static memory retains its contents without the need for periodic refreshing or external causes. This makes it suitable for applications where data needs to be stored reliably without the need for constant power or refreshing cycles.

Option Analysis:

Option A: Dynamic memory requires periodic refreshing to maintain its contents, so it does not fit the description.
Option B: Static memory retains its contents without the need for periodic refreshing or external causes, making it the correct answer.
Option C: RAM (Random Access Memory) is typically dynamic and requires refreshing, so it does not fit the description.
Option D: EEPROM (Electrically Erasable Programmable Read-Only Memory) is non-volatile but can be changed with external causes, so it does not fit the description.

5. When you are typing too fast, the data you type is stored in ..... area.

Correct Answer: Correct answer is: (A) Buffer.

Exam Relevance: Computer Science Exams, IT Certification Exams, Programming Exams

Difficulty: Easy

Concept notes: When typing too fast, the data you type is temporarily stored in a buffer area before it is processed or transferred to the main memory or secondary storage.

Common Mistakes: A common misunderstanding is that the data is directly stored in secondary memory or that all options are correct. However, the buffer is specifically designed to handle temporary data storage during input/output operations.

Explanations: A buffer is a temporary storage area in memory that holds data while it is being transferred from one place to another. When you type too fast, the data is first stored in the buffer to ensure that it is not lost and can be processed at a rate that the system can handle. This prevents data loss and ensures smooth operation.

Option Analysis:

Option A: Correct. The buffer is the temporary storage area for data when typing too fast.
Option B: Incorrect. Secondary memory is used for long-term storage, not for temporary data buffering.
Option C: Incorrect. Not all options are correct; only the buffer is the correct temporary storage area for fast typing.
Option D: Incorrect. There is a correct answer among the options provided.

Mnemonic: Buffer = Bounce Before Final Entry

6. Kilobyte equals to how many bytes?

Correct Answer: Correct answer is: (B) 1024.

Exam Relevance: Computer Science Exams, IT Certification Exams, Data Science Exams

Difficulty: Easy

Concept notes: A kilobyte (KB) is a unit of digital information that equals 1024 bytes.

Common Mistakes: A common mistake is to assume that a kilobyte equals 1000 bytes, which is incorrect in the context of digital memory units.

Explanations: In digital memory units, a kilobyte is defined as 1024 bytes. This is because memory units are based on powers of 2, and 1024 is 2^10. Therefore, a kilobyte is 2^10 bytes, which equals 1024 bytes.

Option Analysis:

Option A: 1064 is incorrect because it does not align with the standard definition of a kilobyte in digital memory units.
Option B: 1024 is the correct number of bytes in a kilobyte, as it is defined as 2^10 bytes.
Option C: This option is incorrect because 1024 is the correct number of bytes in a kilobyte.
Option D: This option is incorrect because not all the options are correct; only 1024 is the correct number of bytes in a kilobyte.

7. Rank the units of data storage in order from smallest to largest..

Correct Answer: Correct answer is: (C) Byte > KB > MB > GB > TB.

Exam Relevance: Computer Science Exams, IT Certification Exams, Data Science Exams

Difficulty: Easy

Concept notes: The units of data storage are ranked from smallest to largest as follows: Byte, Kilobyte (KB), Megabyte (MB), Gigabyte (GB), Terabyte (TB).

Common Mistakes: A common mistake is to confuse the order of these units, particularly the placement of KB and MB.

Explanations: The correct order of data storage units from smallest to largest is Byte, Kilobyte (KB), Megabyte (MB), Gigabyte (GB), and Terabyte (TB). Each unit is 1024 times larger than the previous one. Therefore, Byte is the smallest unit, followed by KB, MB, GB, and TB as the largest.

Option Analysis:

Option A: Incorrect because the order is not from smallest to largest.
Option B: Incorrect because the order is not from smallest to largest.
Option C: Correct because it lists the units from smallest to largest.
Option D: Incorrect because the order is from largest to smallest.

Mnemonic: Bite, Kilo, Mega, Giga, Tera

8. A PC has a total storage capacity of 500 GB. How much storage capacity will the same PC have in terms of MB.

Correct Answer: Correct answer is: (D) 500000 MB.

Exam Relevance: GRE, GMAT, Computer Science Exams, IT Certification Exams

Difficulty: Easy

Concept notes: The conversion between gigabytes (GB) and megabytes (MB) is based on the fact that 1 GB equals 1000 MB.

Common Mistakes: A common mistake is to use the incorrect conversion factor, such as 1 GB = 1024 MB, which is used in some contexts but not in this question.

Explanations: To convert 500 GB to MB, we use the conversion factor 1 GB = 1000 MB. Therefore, 500 GB is equal to 500 * 1000 MB, which equals 500000 MB.

Option Analysis:

Option A: 5000000 MB is incorrect because it is 10 times the correct value.
Option B: 50000 MB is incorrect because it is 1/10 of the correct value.
Option C: 5000 MB is incorrect because it is 1/100 of the correct value.
Option D: 500000 MB is correct because it is the result of multiplying 500 GB by 1000 MB/GB.

9. What is a portion of memory that serves as a temporary repository for data as it waits for a given action?

Correct Answer: Correct answer is: (A) Cache.

Exam Relevance: Computer Science, IT Certification Exams, Engineering Exams

Difficulty: Easy

Concept notes: Cache is a portion of memory that serves as a temporary repository for data as it waits for a given action.

Common Mistakes: A common misunderstanding is that the processor itself serves as the temporary repository, but the processor is responsible for processing data, not storing it temporarily.

Explanations: Cache is a high-speed memory that stores frequently accessed data to speed up access times. It acts as a temporary repository, holding data that is likely to be used again soon, thus reducing the need to fetch data from slower main memory or storage devices.

Option Analysis:

Option A: Cache is the correct answer as it is a temporary memory that stores data for quick access.
Option B: Processor is the component that performs computations and processes data, not a temporary storage unit.
Option C: Processor pool is a collection of processors, not a temporary storage unit.
Option D: Bank typically refers to a group of memory modules, not a temporary storage unit.

10. The ALU of a computer normally contains a number of high speed storage element called

Correct Answer: Correct answer is: (B) Registers.

Exam Relevance: Computer Architecture, Digital Logic, Computer Organization

Difficulty: Easy

Concept notes: Registers are high-speed storage elements within the ALU (Arithmetic Logic Unit) of a computer. They are used to temporarily hold data and instructions for processing.

Common Mistakes: A common misunderstanding is that semiconductor memory or hard disks are part of the ALU. However, these are external storage devices and not part of the ALU's internal structure.

Explanations: Registers are high-speed storage elements within the ALU. They are designed to hold data and instructions temporarily for immediate processing. This makes them essential for the ALU to perform operations efficiently. Other options like semiconductor memory, hard disks, and magnetic disks are not part of the ALU and are used for different purposes.

Option Analysis:

Option A: Semiconductor memory is not part of the ALU; it is a type of external memory used for storing data and instructions.
Option B: Registers are high-speed storage elements within the ALU, used for temporary storage of data and instructions.
Option C: Hard disks are external storage devices and not part of the ALU.
Option D: Magnetic disks are also external storage devices and not part of the ALU.

Frequently Asked Questions

What is the difference between volatile and non-volatile memory?

Volatile memory, such as RAM, loses its data when the power is turned off, while non-volatile memory, like ROM or flash memory, retains data even without power.

How do memory units convert between gigabytes and megabytes?

To convert gigabytes to megabytes, multiply the number of gigabytes by 1024. For example, 1 gigabyte is equal to 1024 megabytes.

What is the role of cache memory in a computer system?

Cache memory is a small, fast memory that stores frequently accessed data to speed up the retrieval process, reducing the time the CPU spends waiting for data from slower main memory.

What is the significance of binary information in digital memory units?

Binary information, consisting of bits (0s and 1s), is the fundamental unit of data in digital memory. It allows for the representation and storage of all types of digital information.

How does virtual memory enhance a computer's performance?

Virtual memory extends the available memory by temporarily transferring data from RAM to the hard drive, allowing the system to handle larger programs and more data than the physical RAM can hold.

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